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• Posted by a hidden member.
Three men decided to split the cost of a hotel room. The hotel manager gave them a price of \$30. The men split the bill evenly, each paying \$10, and retired to their room.

However, the manager realized that it was a Wednesday night, which meant the hotel had a special: rooms were only \$25. He had overcharged them \$5!

He promptly called the bellboy, gave him five one-dollar bills and told him to return it to the men. When the bellboy explained the situation to the men, they were so pleased at the honesty of the establishment that they promptly tipped the bellboy \$2 of the \$5 he had returned and each kept \$1 for himself.

The Problem: Each of the three men ended up paying \$9 (their original \$10, minus \$1 back) totaling \$27, plus \$2 for the bellboy makes \$29. Where did the extra dollar go?

Ok men, what is the answer?
• Posted by a hidden member.
It's a problem on commutativity and improper grouping I think. Wrong order = wrong answer.

First of all, they did NOT pay \$9. They actually paid \$25 for the room - which amounts to 8.3333 each.

Of the 5 dollars, they're supposed to get back \$1.6667 each, but they gave away \$2, which nicely rounds off to \$1 each, and each paying \$0.6667 to the bellboy. This should be treated as a separate equation since the current \$5 has no more bearing on the \$25 they originally paid.

(2+3)+(25)=30

Voila.

It's an illusion created by ordering I think.

• Posted by a hidden member.
It is the way the question has been worded.

30 minus 3 equals 27

27 minus 2 equals 25

It is not 27 plus 2, this is the part that is put in to confuse you. There is no extra buck.
• Posted by a hidden member.
Good work boys. You both are right.
Faulty was in the wording.

Logic Puzzle:
This one should be simple enough.

"How can you throw a ball as hard as you can and have it come back to you, even if it doesn't hit anything, there is nothing attached to it, and no one else catches or throws it?"
• Posted by a hidden member.
up
• Posted by a hidden member.
Mind if I join in ?

Which of the black shapes are exactly the same as the red shape ?

There may be more than one answer.

• Posted by a hidden member.
onmyway saidMind if I join in ?

Which of the black shapes are exactly the same as the red shape ?

There may be more than one answer.

A, E, & F
• Posted by a hidden member.